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Joule Thief Notes

Random related thoughts.

The amperage to the load depends on the load's impedance and the input voltage. I_{load}={V_{input}/R_{load}}*efficiency

Making Meters

Making some meters. http://campus.udayton.edu/~physics/gkm/p207ch28.htm

Ig Rg = (Imax - Ig) RA

Vmax = Ig(Rg + RV)

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Some questions

                            //
Flasher?                 +-->|--+
                         |      |
                   +->|--+--||--+
                   |            |
+------------------+    _+------+
|                 C \   / E     |
|                   -----       |
|  =======            |B        |
+--UUU+UUU--+--/\/\/--+         |
A2    |    B1                   |
      |                         |
      +----||-------------------+
      |                         |
      +---/\/\/---+1V          ---
                                -

References