Chapter 14

David Wagner 2007/08/08 09:11

Problem 1

[pg.430,422]A_{brick}= {(2.25+.5)*(8+.5)}/{144} =0.1623 ft²

A_{wall}=8*30- {48*72}/{144} - {3*26*48}/{144} =190 ft²

N={1.03*2*190}/{.1623} =2412 bricks

2412 bricks

Problem 2

Assume 5% waste, ½” joints.

A_{brick}= {(2.25+.5)*(8+.5)}/{144} =0.1623 ft²

A_{wall}=8*100 - 4*{8/12}*8 - {{36*80}/144} - {{10*30*48}/144}=658.7 ft²

N={658.7/0.1623}*2*1.05=8523; C=8523*{880/1000}=$7500

8523 bricks$7500

Problem 3

  • A course is a horizontal layer of bricks.
  • A wythe is a vertical wall layer.

Problem 4

  1. Store masonry units onsite covered by a tarp.
  2. Protect masonry walls by covering them with a tarp and heating if necessary so the mortar cures properly.

Problem 5

2”

Problem 6

[pg423 eq.14-1] This problem refers to problem #1. t=½”

V_{brick}=t*w*(l+h+t)= {0.5*3.75*(8+2+0.5)}/{12*12*12} =0.0122 ft³

V_{wythe}=0.0122*{2412/2}=14.7 ft³

V_{gap}=0.625*190*12=9.9 ft³

V_{total}=1.25*9.9*2*4.7=49.125 ft³

49.125 ft³

Problem 7

[pg.424 eq.14-2, tbl.14-4]H_s=dt/8 = 60*{6/12}*{1/15}=2

2'

Problem 8

This reinforcing might be needed where earthquakes or hurricanes are likely.

Problem 9

Mortar may be used for 2½ hours after initial mixing.

Problem 10

[Programming Problem]


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