Table of Contents
Chapter 2

— David Wagner 2007/06/29 15:40

Problem 1.

A=20*50+26*17 =1842 sf

d_{avg}={8.2+6.6+6.0+6.4+6.8+7.4}/6=7 ft

V={1842*7}/27=478

478 BCY

Problem 2.

  • Swell: 25% [Tbl 2-5]
  • Angle of Repose: 32º [tbl 2-6]
  • Excavation: A*Swell=4*5*1.25=25 cf/ft

b=sqrt{{4V}/{L tan R}}=sqrt{{4*25}/{1*tan(32)}}=12.65 ft

h={{B tan R}/{2}}=3.95 ft

b=12.65 ft, h=3.95 ft

Problem 3.

Is >50% larger than ¼” → Gravel

GM

Problem 4.

L=1 yd; V=1.3*1*24/27= 0.89 BCY/yd; R=35°

B=sqrt{{4V}/{L*tanR}}=sqrt{{4*0.89}/{1*tan 35}}=5.08 yd

H={{B*tanR}/{2}}={5*tan 35}/{2}}=1.78 yd

B=15', H=5.3'

Problem 5.

V_{loose}=1000000*{3650/2500}=1460000 LCY; Trucks: 1460000/6=243000

243,000 trips

Problem 6.

60*0.52=31.2

31.2 min/hr

Problem 7.

a.

  • Cut: 150+100=250,000 BCY
  • Fill: 80+120+100=300,000 BCY
  • Waste: 0
  • Borrow: 50,000 BCY

b.

  • Haul Length 3: 6700-5100=1600'

Problem 8.

LF=gamma_{loose}/gamma_{packed}=2500/3100=0.81 SF=gamma_{bank}/gamma_{compact}=3100/3650=0.85

LF:0.81SF:0.85

Problem 9.

MC={WW-DW}/{DW}*100%={15.0-14.2}/{14.2}=5.6%

Moisture Content:5.6%

Discussion


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