Chapter 3

— David Wagner 2007/06/29 15:40

Problem 1.

P=Ideal*SDfactor*Efficiency*Swell=230*1.06*{50/60}*1.25= 253

8.9/9.9= 90%

253 LCY/hr

P=CSVBE=150*0.83*3.5*0.8*.75= 296 LCY; 296*0.77= 228 BCY

228 BCY/hr

Lasers and TV cameras are used to verify aligment and boring depth.

FF=0.95; BL=0.95 cy; E=0.8 P=0.95*{3600/25}*0.8= 109

109 cy/hr

17950-604-298=17048

17,048 lb

W=10000+1200=11200 → R≤180'

180'

C: 160 cyc/hr; S: 1.15+{{1.21-1.15}/3}= 1.17; V: 0.75 cy; B: 0.80; E: 0.7; TAF: 0.95; LF=0.77; AT=30/36 * 5/3 = 1.4 sy

$P_{LCY}=C*S*V*B*E=160*1.17*0.75*0.8*0.7*0.95=$ 74.7 LCY/hr

$P_{BCY}=P_{LCY}*LF=74.7*0.77=$ 57.5 BCY/hr

$P_{trench}=3*{57.5/1.4}=$ 123 ft/hr

123 ft/hr

C: 160 cyc/hr; S: 1.08; V: 1.5 cy; B: 0.90; E: 50/60; LF=0.80;

$P_{LCY}=C*S*V*B*E=160*1.08*1.5*0.9*{50/60}=$ 194.4 LCY/hr

$P_{BCY}=P_{LCY}*LF=194.4*0.8=$ 155.5 BCY/hr

55.5 BCY/hr