Table of Contents
Chapter 9
— David Wagner 2007/06/29 15:40
Problem 1.
- Hose Pressure Drop [tbl 9-6]:
2.4 psig - Manifold Pressure Drop: 2.5 psig
- Pressure at Outlet: 110-(90+2.4+2.5)=15.1 psig
- Loss/1000': 15.1/1400 → 10.8 psig/1000'
- Flow: 3*110*1.07=353 cfm
- Drop of 2” Pipe: 9.4 < 10.8
| 2” Diameter Pipe |
|---|
Problem 2.
Submersible pumps are usually used when a great deal of suction lift would otherwise be required. Jet pumps and air-lift pumps may also be used.
Problem 3.
| 9' |
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Problem 4.
- 100' of 3” hose; Q=200 gpm
- SH=10+20=30' [tbl 9-8] → 9.6/100' * 100' = 9.6 ft=FH
- TH=SH+FH = 30+9.6=39.6' [tbl 9-9]→
| Model 15M Pump:40/10/241 |
|---|
Problem 5.
- SH: 50' [fig 9-4]; Elbows: 3*11'=33'; CV: 1*25'; FV: 70'
- Pipe: 300'+33+25+70=468'; 4”@280gpm [tbl 9-9]: 5.4'/100'*400'=25.3'
- Hose: 4.3'/100'*20'=0.8'
- FH: 25.3+0.8=26.1'; TH=50+26.1=76.1'
| Model 40M Pump |
|---|
Problem 6.
- 4*200/.95=842 cfm
- 4” Pipe: 1500'
- Gate Valve: 2*2.3'=4.6'
- Elbows: 6*11'=66
Equivalent Length of 4” Pipe: 1570.6'
- Pipe: -1570.6'*1.6/1000'= -2.5 psig
- Manifold: -3 psig
Pressure at Manifold: 100-5.5= 94.5 psig
- 1.25” hose: -1.048*100'*25.9/1000'= -2.7 psig
Pressure at each dirll=94.5-2.7=91.8
| 92 psig |
|---|
Problem 7.
- 2*800+1*1100+5*100=3200 cfm
4376
| 4376 cfm |
|---|
Problem 8.
Air compressor capacity is rated as as the STP volume of air the compressor will deliver at as specified pressure.
Problem 9.
The pressure loss in a pipeline decreases as the initial pressure increases.
Discussion