Table of Contents
Handout "Chapter 4"

— David Wagner 2007/06/29 15:40

Problem 4-1.

I=1+{{500000-LH}/1000000}=1+{{500000-350000}/1000000}=1.15

1.15

Problem 4-2.

{5400-360-1152-785-1084}/{5400}=2019/5400=0.3738

37%

Problem 4-3.

% OvertimeProductivity Index
x I=1-0.8x^2
0.0 1.00
0.1 0.99
0.2 0.97
0.3 0.93
0.4 0.87
0.5 0.80

JpGraph Table Data Plot

Problem 4-4.

Labor-hoursProductivity Index
x I=-0.016x^2+0.16x+0.6
0 0.60
1 0.74
2 0.86
3 0.94
4 0.98
5 1.00

JpGraph Table Data Plot

Problem 4-5.

E(T)=Sigma t P(b)=0.6+1.3+3.5+5.25+2.4+1.7=14.75 ≈ 15 days

Expected delivery date is 15 days from order date. To expect it one day earlier, order one day earlier.

Problem 4-6.

Power Shovel Production: {2*LCY*BCY*60*sec*60*min*8*hr} / {1.05*LCY*80*sec*min*hr*day}=685.7 BCY/day = 720 LCY/day

Dump Truck Cycle Time: 40*sec + {6*mi*hr*day}/{30*mi*8*hr}=(40+)*sec=0.025 day

Dump Truck Production: {8*LCY}/{0.025 day}=320 LCY/day

Three trucks are needed.

Problem 4-7.

P prime_c = 720*0.972*0.960*0.750*0.750=377.91

378 yd³/day

T prime_c = {1*8*3600}/{378}=76.19

76 sec

Problem 4-8.

T prime_c = {0.025}/{0.85*0.80}=0.036765 day

P_h = {8}/{0.036765}=217.6

218 yd³/day

N_h = {1.05*378}/{218}=1.824

2 trucks

Problem 4-9.

a. P_e={1.5*8*3600}/{60}=720 yd³

b. T_h={{2*5*3600}/{25}} + 75=1515 sec; P_h = {7.5*8*3600}/{1515}=142.6 yd³ N_h={1.08*720}/{142.6}=5.454 → 6 trucks

c. P prime_e=720*0.940*0.952*0.850*0.750=411 yd³; T prime_e={60}/{720*0.940*0.952*0.850*0.750}105 sec

d. P prime_h = 142.6*0.952*0.700*0.750=71.3 yd³; N_h={1.08*411}/{71.3}=6.2 → 7 trucks

Discussion


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