Table of Contents
— David Wagner 2009/09/15 19:52
EGR 6013 Homework Set 1 (6-11)
Problem 6.
[A][A] = 0 =
=
.
=
=
⇒
Problem 7.
Show [E] = [A][C] =
,
,
,
.
.
.
=
Continuing to substitute the results of these multiplications leads directly to the long form of the series definition of this matrix product.
=
= [A][C].
Problem 10.
Prove |[A][B]| = |[A]||[B]|.
[A][B] =
|[A][B]| =
=
=
=
=
=
Problem 11.
is arbitrary and has no effect on λ.
⇒
Now it seems
is messed up,
and all that is left is λ=-3/2 and the trivial solution λ=0.
For λ=-3/2,
.
Going back to equation 2,
=
⇒
⇒

