EGR 6013 Homework Set 2 (50-55)

David Wagner 2009/09/20 01:09

Problem 50.

(a) Determine the characteristic numbers (λ1, λ2) and corresponding unit characteristic vectors ({e1}, {e2}) of the matrix

  • Lambda = delim{[}{ matrix{2}{2}{ 5 2 2 2 } }{]}.

(b) Verify that {e1} and {e1} are orthogonal.

© if {v} = {1, 1}, determine α1 and α1 so that

  • {v} = alpha_1 delim{lbrace}{e_1}{rbrace} + alpha_2 delim{lbrace}{e_2}{rbrace}.

(d) Use the results of (a), together with equation (105), to obtain the solution of the following set of equations:

  • 5x_1 + 2x_2 = lambda x_1 + 2,
  • 2x_1 + 2x_2 = lambda x_2 + 1.

Consider the exceptional case separately.

(105) delim{lbrace}{x}{rbrace} 
= sum{k=1}{n}{} {(delim{lbrace}{e_k}{rbrace},delim{lbrace}{c}{rbrace})
 /{lambda_k - lambda}}
 delim{lbrace}{e_k}{rbrace}

Problem 51.

(a) Suppose that the n characteristic vectors of the real symmetric matrix [A] are not normalized (reduced to unit length). If they are denoted by {u1}, {u2}, … ,{un}, show that (105) must be replaced by the equation

  • x = sum {k=1}{n}{
 {{(u_k, c)}/{lambda_k - lambda}}
 {{u_k}/{(u_k, u_k)}} }.

(b) Verify this result in the case of Problem 50(d).

Section 1.13.

√Problem 54.

Construct a set of three mutually orthogonal unit vectors which are linear combinations of the vectors {1, 0, 2, 2}, {1, 1, 0, 1}, {1, 1, 0, 0}.

e_3 = {sqrt{2}/2}
delim{lbrace}{matrix{4}{1}{ 1 1 0 0
 } }{rbrace}
 = delim{lbrace}{matrix{4}{1}{
{sqrt{2}/2} {sqrt{2}/2} {0} {0}
 } }{rbrace}.

v_2 = 
delim{lbrace}{matrix{4}{1}{ 1 1 0 1
 } }{rbrace}
 - 
delim{]}{matrix{1}{4}{ {sqrt{2}/2} {sqrt{2}/2} {0} {0}
 } }{[}

delim{lbrace}{matrix{4}{1}{ 1 1 0 1
 } }{rbrace}

delim{lbrace}{matrix{4}{1}{ {sqrt{2}/2} {sqrt{2}/2} {0} {0}
 } }{rbrace} = delim{lbrace}{matrix{4}{1}{ 1 1 0 1
 } }{rbrace}
- sqrt{2}
delim{lbrace}{matrix{4}{1}{ {sqrt{2}/2} {sqrt{2}/2} {0} {0}
 } }{rbrace}
=
delim{lbrace}{matrix{4}{1}{ 0 0 0 1
 } }{rbrace}

e_2 =
delim{lbrace}{matrix{4}{1}{ 0 0 0 1
 } }{rbrace}

v_1 = 
delim{lbrace}{matrix{4}{1}{ 1 0 2 2
 } }{rbrace}
 - 
delim{]}{matrix{1}{4}{ {sqrt{2}/2} {sqrt{2}/2} {0} {0}
 } }{[}
delim{lbrace}{matrix{4}{1}{ 1 0 2 2
 } }{rbrace}
delim{lbrace}{matrix{4}{1}{ {sqrt{2}/2} {sqrt{2}/2} {0} {0}
 } }{rbrace}
 - 
delim{]}{matrix{1}{4}{ 0 0 0 1
 } }{[}
delim{lbrace}{matrix{4}{1}{ 1 0 2 2
 } }{rbrace}
delim{lbrace}{matrix{4}{1}{ 0 0 0 1
 } }{rbrace} = delim{lbrace}{matrix{4}{1}{ 1 0 2 2
 } }{rbrace}
 - 
{sqrt{2}/2}
delim{lbrace}{matrix{4}{1}{ {sqrt{2}/2} {sqrt{2}/2} {0} {0}
 } }{rbrace}
 - 2
delim{lbrace}{matrix{4}{1}{ 0 0 0 1
 } }{rbrace} = delim{lbrace}{matrix{4}{1}{ 1 0 2 2
 } }{rbrace}
 - 
delim{lbrace}{matrix{4}{1}{ {1/2} {1/2} {0} {0}
 } }{rbrace}
 - 
delim{lbrace}{matrix{4}{1}{ 0 0 0 2
 } }{rbrace} = delim{lbrace}{matrix{4}{1}{ {1/2} {-1/2} 2 0
 } }{rbrace}

e_1={sqrt{2}/3}delim{lbrace}{matrix{4}{1}{ {1/2} {-1/2} 2 0
 } }{rbrace} = delim{lbrace}{matrix{4}{1}{ {sqrt{2}/6} {-sqrt{2}/6} {{2sqrt{2}}/3} 0
 } }{rbrace}

The three unit vectors e are delim{lbrace}{matrix{4}{1}{ {sqrt{2}/6} {-sqrt{2}/6} {{2sqrt{2}}/3} 0
 } }{rbrace}, delim{lbrace}{matrix{4}{1}{ 0 0 0 1
 } }{rbrace}, delim{lbrace}{matrix{4}{1}{
{sqrt{2}/2} {sqrt{2}/2} {0} {0}
 } }{rbrace}.

√Problem 55.

Prove that the vector {v} = {2, 1, 2, 0} is in the space generated by the three vectors defined in Problem 54 and express {v} as a linear combination of the selected vectors {e1}, {e2}, and {e3}.

This is true if {v} can be made from a linear combination of {ei}: [e]{c}={v}.

delim{[}{matrix{4}{3}{
{sqrt{2}/6}    0 {sqrt{2}/2}
{-sqrt{2}/6}   0 {sqrt{2}/2}
{{2sqrt{2}}/3} 0 0
0              1 0
 } }{]}
delim{lbrace}{matrix{3}{1}{ c_1 c_2 c_3
 } }{rbrace}
=
delim{lbrace}{matrix{4}{1}{ 2 1 2 0
 } }{rbrace}

delim{[}{matrix{4}{3}{
{1}    0 {3}
{-sqrt{2}/6}   0 {sqrt{2}/2}
{{2sqrt{2}}/3} 0 0
0              1 0
 } }{]}
delim{lbrace}{matrix{3}{1}{ c_1 c_2 c_3
 } }{rbrace}
=
delim{lbrace}{matrix{4}{1}{ {12/sqrt{2} } 1 2 0
 } }{rbrace}

delim{[}{matrix{4}{3}{
{1}    0 {3}
{-sqrt{2}/6}   0 {{sqrt{2}}/2}
{{2sqrt{2}}/3} 0 0
0              1 0
 } }{]}
delim{lbrace}{matrix{3}{1}{ c_1 c_2 c_3
 } }{rbrace}
=
delim{lbrace}{matrix{4}{1}{ {6sqrt{2}} 1 2 0
 } }{rbrace}

delim{[}{matrix{4}{3}{
1   0 {3}
0   0 {sqrt{2}}
0   0 {-2sqrt{2}}
0   1 0
 } }{]}
delim{lbrace}{matrix{3}{1}{ c_1 c_2 c_3
 } }{rbrace}
=
delim{lbrace}{matrix{4}{1}{ {6sqrt{2}} 3 {-6} 0
 } }{rbrace}

  • c_2 = 0
  • -2sqrt{2} c_3 = {-6}c_3= {3/sqrt{2}}={{3sqrt{2}}/2}
  • {sqrt{2}}c_3 = 3c_3=3/sqrt{2} = {{3sqrt{2}}/2}
  • c_1 + 3c_3=6sqrt{2} = c_1 + {{9sqrt{2}}/2}={12sqrt{2}}/2c_1={3sqrt{2}}/2

{v}
=delim{lbrace}{matrix{4}{1}{ 2 1 2 0
 } }{rbrace}
=
delim{[}{matrix{4}{3}{
{sqrt{2}/6}    0 {sqrt{2}/2}
{-sqrt{2}/6}   0 {sqrt{2}/2}
{{2sqrt{2}}/3} 0 0
0              1 0
 } }{]}
delim{lbrace}{matrix{3}{1}{ {{3sqrt{2}}/2} {0} {{{3sqrt{2}}/2}}
 } }{rbrace}


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